Methyl 4-chloro-1-(4-chlorophenyl)-6-oxo-1,6-dihydro-3-pyridazinecarboxylate

• CAS: 129109-19-9
• Catalog Number: ACM129109199
• Category: Other Products
• Molecular Weight: 299.11
• Molecular Formula: C₁₂H₈Cl₂N₂O₃
• Synonyms: METHYL 4-CHLORO-1-(4-CHLOROPHENYL)-6-OXO-1,6-DIHYDRO-3-PYRIDAZINECARBOXYLATE;Methyl 4-chloro-1-(4-chlorophenyl)-6-oxo-1,6-dihydropyridazine-3-carboxylate
• Melting Point: 167-169°C

Custom Q&A

What is the molecular formula of Methyl 4-chloro-1-(4-chlorophenyl)-6-oxo-1,6-dihydro-3-pyridazinecarboxylate?

The molecular formula is C12H8Cl2N2O3.

When was Methyl 4-chloro-1-(4-chlorophenyl)-6-oxo-1,6-dihydro-3-pyridazinecarboxylate created in PubChem?

It was created on July 19, 2005.

What is the molecular weight of Methyl 4-chloro-1-(4-chlorophenyl)-6-oxo-1,6-dihydro-3-pyridazinecarboxylate?

The molecular weight is 299.11 g/mol.

What are some synonyms for Methyl 4-chloro-1-(4-chlorophenyl)-6-oxo-1,6-dihydro-3-pyridazinecarboxylate?

Some synonyms include methyl 4-chloro-1-(4-chlorophenyl)-6-oxo-1,6-dihydropyridazine-3-carboxylate and methyl 4-chloro-1-(4-chlorophenyl)-6-oxopyridazine-3-carboxylate.

What is the InChIKey for Methyl 4-chloro-1-(4-chlorophenyl)-6-oxo-1,6-dihydro-3-pyridazinecarboxylate?

The InChIKey is CBOGCPKOHRRUET-UHFFFAOYSA-N.

What is the XLogP3-AA value for Methyl 4-chloro-1-(4-chlorophenyl)-6-oxo-1,6-dihydro-3-pyridazinecarboxylate?

The XLogP3-AA value is 2.8.

How many hydrogen bond acceptor counts does Methyl 4-chloro-1-(4-chlorophenyl)-6-oxo-1,6-dihydro-3-pyridazinecarboxylate have?

It has 4 hydrogen bond acceptors.

What is the topological polar surface area of Methyl 4-chloro-1-(4-chlorophenyl)-6-oxo-1,6-dihydro-3-pyridazinecarboxylate?

The topological polar surface area is 59 Ų.

Does Methyl 4-chloro-1-(4-chlorophenyl)-6-oxo-1,6-dihydro-3-pyridazinecarboxylate have any defined atom stereocenter count?

No, it does not have any defined atom stereocenter count.

Is Methyl 4-chloro-1-(4-chlorophenyl)-6-oxo-1,6-dihydro-3-pyridazinecarboxylate a canonicalized compound?

Yes, it is a canonicalized compound.