Dibromo(1,5-cyclooctadiene)platinum(II)

• CAS: 12145-48-1
• Catalog Number: ACM12145481-1
• Category: Platinum series of catalysts
• Molecular Weight: 463.07
• Molecular Formula: C8H12Br2Pt
• Synonyms: (1Z,5Z)-Cycloocta-1,5-diene;dibromoplatinum
• IUPAC Name: (1Z,5Z)-cycloocta-1,5-diene;dibromoplatinum
• Canonical SMILES: C1CC=CCCC=C1.Br[Pt]Br
• InChI: InChI=1S/C8H12.2BrH.Pt/c1-2-4-6-8-7-5-3-1;/h1-2,7-8H,3-6H2;2*1H;/q;+2/p-2/b2-1-,8-7-
• InChI Key: HFLCCHAOKSABAA-PHFPKPIQSA-L
• Boiling Point: 153.5ºC at 760 mmHg
• Flash Point: 31.7ºC
• Appearance: Powder
• Exact Mass: 462.89332
• Hazard Statements: Xi
• H-Bond Acceptor: 0
• H-Bond Donor: 0
• Hydrogen Bond Acceptor Count: 0
• Hydrogen Bond Donor Count: 0
• Isomeric SMILES: C1/C=C\CC/C=C\C1.Br[Pt]Br
• MDL Number: MFCD00058724
• Monoisotopic Mass: 460.89537
• Rotatable Bond Count: 0
• Safety Description: S26
• Symbol: GHS07
• Topological Polar Surface Area: 0 Ų

Custom Q&A

What is the molecular formula of Dibromo(1,5-cyclooctadiene)platinum(II)?

The molecular formula is C8H12Br2Pt.

What is the molecular weight of Dibromo(1,5-cyclooctadiene)platinum(II)?

The molecular weight is 463.07 g/mol.

What is the IUPAC name of Dibromo(1,5-cyclooctadiene)platinum(II)?

The IUPAC name is (1Z,5Z)-cycloocta-1,5-diene;dibromoplatinum.

What is the InChIKey of Dibromo(1,5-cyclooctadiene)platinum(II)?

The InChIKey is HFLCCHAOKSABAA-PHFPKPIQSA-L.

What is the canonical SMILES representation of Dibromo(1,5-cyclooctadiene)platinum(II)?

The canonical SMILES is C1CC=CCCC=C1.Br[Pt]Br.

What is the CAS number of Dibromo(1,5-cyclooctadiene)platinum(II)?

The CAS number is 12145-48-1.

What is the EC number of Dibromo(1,5-cyclooctadiene)platinum(II)?

The EC number is 621-603-0.

What is the hydrogen bond donor count of Dibromo(1,5-cyclooctadiene)platinum(II)?

The hydrogen bond donor count is 0.

What is the hydrogen bond acceptor count of Dibromo(1,5-cyclooctadiene)platinum(II)?

The hydrogen bond acceptor count is 0.

Is Dibromo(1,5-cyclooctadiene)platinum(II) a canonicalized compound?

Yes, it is a canonicalized compound.